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113 lines
3.6 KiB
113 lines
3.6 KiB
2 years ago
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from math import gcd
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import numpy as np
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from numpy.linalg import norm, solve
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from cmmde_bulk import bulk
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def surface(lattice, indices, layers, vacuum=None, tol=1e-10, periodic=False):
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"""Create surface from a given lattice and Miller indices.
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lattice: Atoms object or str
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Bulk lattice structure of alloy or pure metal. Note that the
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unit-cell must be the conventional cell - not the primitive cell.
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One can also give the chemical symbol as a string, in which case the
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correct bulk lattice will be generated automatically.
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indices: sequence of three int
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Surface normal in Miller indices (h,k,l).
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layers: int
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Number of equivalent layers of the slab.
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vacuum: float
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Amount of vacuum added on both sides of the slab.
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periodic: bool
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Whether the surface is periodic in the normal to the surface
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"""
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indices = np.asarray(indices)
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if indices.shape != (3,) or not indices.any() or indices.dtype != int:
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raise ValueError('%s is an invalid surface type' % indices)
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if isinstance(lattice, str):
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lattice = bulk(lattice, cubic=True)
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h, k, l = indices
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h0, k0, l0 = (indices == 0)
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if h0 and k0 or h0 and l0 or k0 and l0: # if two indices are zero
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if not h0:
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c1, c2, c3 = [(0, 1, 0), (0, 0, 1), (1, 0, 0)]
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if not k0:
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c1, c2, c3 = [(0, 0, 1), (1, 0, 0), (0, 1, 0)]
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if not l0:
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c1, c2, c3 = [(1, 0, 0), (0, 1, 0), (0, 0, 1)]
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else:
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p, q = ext_gcd(k, l)
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a1, a2, a3 = lattice.cell
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# constants describing the dot product of basis c1 and c2:
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# dot(c1,c2) = k1+i*k2, i in Z
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k1 = np.dot(p * (k * a1 - h * a2) + q * (l * a1 - h * a3),
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l * a2 - k * a3)
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k2 = np.dot(l * (k * a1 - h * a2) - k * (l * a1 - h * a3),
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l * a2 - k * a3)
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if abs(k2) > tol:
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i = -int(round(k1 / k2)) # i corresponding to the optimal basis
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p, q = p + i * l, q - i * k
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a, b = ext_gcd(p * k + q * l, h)
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c1 = (p * k + q * l, -p * h, -q * h)
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c2 = np.array((0, l, -k)) // abs(gcd(l, k))
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c3 = (b, a * p, a * q)
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surf = build(lattice, np.array([c1, c2, c3]), layers, tol, periodic)
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if vacuum is not None:
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surf.center(vacuum=vacuum, axis=2)
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return surf
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def build(lattice, basis, layers, tol, periodic):
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surf = lattice.copy()
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scaled = solve(basis.T, surf.get_scaled_positions().T).T
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scaled -= np.floor(scaled + tol)
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surf.set_scaled_positions(scaled)
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surf.set_cell(np.dot(basis, surf.cell), scale_atoms=True)
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surf *= (1, 1, layers)
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a1, a2, a3 = surf.cell
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surf.set_cell([a1, a2,
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np.cross(a1, a2) * np.dot(a3, np.cross(a1, a2)) /
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norm(np.cross(a1, a2))**2])
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# Change unit cell to have the x-axis parallel with a surface vector
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# and z perpendicular to the surface:
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a1, a2, a3 = surf.cell
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surf.set_cell([(norm(a1), 0, 0),
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(np.dot(a1, a2) / norm(a1),
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np.sqrt(norm(a2)**2 - (np.dot(a1, a2) / norm(a1))**2), 0),
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(0, 0, norm(a3))],
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scale_atoms=True)
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surf.pbc = (True, True, periodic)
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# Move atoms into the unit cell:
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scaled = surf.get_scaled_positions()
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scaled[:, :2] %= 1
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surf.set_scaled_positions(scaled)
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if not periodic:
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surf.cell[2] = 0.0
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return surf
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def ext_gcd(a, b):
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if b == 0:
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return 1, 0
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elif a % b == 0:
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return 0, 1
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else:
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x, y = ext_gcd(b, a % b)
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return y, x - y * (a // b)
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